10x^2+1x-6=0

Solution for 10x^2+1x-6=0 equation:

10x^2+1x-6=0

We add all the numbers together, and all the variables

10x^2+x-6=0

a = 10; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·10·(-6)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*10}=\frac{-1-\sqrt{241}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*10}=\frac{-1+\sqrt{241}}{20}
$